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(7y+2)=(2y+4)
We move all terms to the left:
(7y+2)-((2y+4))=0
We get rid of parentheses
7y-((2y+4))+2=0
We calculate terms in parentheses: -((2y+4)), so:We get rid of parentheses
(2y+4)
We get rid of parentheses
2y+4
Back to the equation:
-(2y+4)
7y-2y-4+2=0
We add all the numbers together, and all the variables
5y-2=0
We move all terms containing y to the left, all other terms to the right
5y=2
y=2/5
y=2/5
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