(7y+5)/3=(8y+6)/2

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Solution for (7y+5)/3=(8y+6)/2 equation: 



(7y+5)/3=(8y+6)/2

We move all terms to the left:

(7y+5)/3-((8y+6)/2)=0

We calculate fractions


7y/()+(-((8y+6)*3)/()=0



We calculate terms in parentheses: +(-((8y+6)*3)/(), so:

-((8y+6)*3)/(

We multiply all the terms by the denominator


-((8y+6)*3)



We calculate terms in parentheses: -((8y+6)*3), so:

(8y+6)*3

We multiply parentheses

24y+18

Back to the equation:

-(24y+18)



We get rid of parentheses

-24y-18

Back to the equation:

+(-24y-18)



We get rid of parentheses

7y/()-24y-18=0

We multiply all the terms by the denominator


7y-24y*()-18*()=0

We add all the numbers together, and all the variables

7y-24y*()=0

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