(7y-11)=(2y+7)=(3y-8)

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Solution for (7y-11)=(2y+7)=(3y-8) equation: 



(7y-11)=(2y+7)=(3y-8)

We move all terms to the left:

(7y-11)-((2y+7))=0

We get rid of parentheses

7y-((2y+7))-11=0



We calculate terms in parentheses: -((2y+7)), so:

(2y+7)

We get rid of parentheses

2y+7

Back to the equation:

-(2y+7)



We get rid of parentheses

7y-2y-7-11=0

We add all the numbers together, and all the variables

5y-18=0

We move all terms containing y to the left, all other terms to the right

5y=18

y=18/5

y=3+3/5

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