(7y-13)=(3y+35)

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Solution for (7y-13)=(3y+35) equation: 



(7y-13)=(3y+35)

We move all terms to the left:

(7y-13)-((3y+35))=0

We get rid of parentheses

7y-((3y+35))-13=0



We calculate terms in parentheses: -((3y+35)), so:

(3y+35)

We get rid of parentheses

3y+35

Back to the equation:

-(3y+35)



We get rid of parentheses

7y-3y-35-13=0

We add all the numbers together, and all the variables

4y-48=0

We move all terms containing y to the left, all other terms to the right

4y=48

y=48/4

y=12

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