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(7y-4)/(2y+11)=9/5
We move all terms to the left:
(7y-4)/(2y+11)-(9/5)=0
Domain of the equation: (2y+11)!=0We add all the numbers together, and all the variables
We move all terms containing y to the left, all other terms to the right
2y!=-11
y!=-11/2
y!=-5+1/2
y∈R
(7y-4)/(2y+11)-(+9/5)=0
We get rid of parentheses
(7y-4)/(2y+11)-9/5=0
We calculate fractions
(35y-20)/(10y+55)+(-18y-99)/(10y+55)=0
We multiply all the terms by the denominator
(35y-20)+(-18y-99)=0
We get rid of parentheses
35y-18y-20-99=0
We add all the numbers together, and all the variables
17y-119=0
We move all terms containing y to the left, all other terms to the right
17y=119
y=119/17
y=7
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