(7y-8)+(2y+20)=(7y-2y)+(8+20)

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Solution for (7y-8)+(2y+20)=(7y-2y)+(8+20) equation: 



(7y-8)+(2y+20)=(7y-2y)+(8+20)

We move all terms to the left:

(7y-8)+(2y+20)-((7y-2y)+(8+20))=0

We add all the numbers together, and all the variables

(7y-8)+(2y+20)-((+5y)+28)=0

We get rid of parentheses

7y+2y-((+5y)+28)-8+20=0



We calculate terms in parentheses: -((+5y)+28), so:

(+5y)+28

We get rid of parentheses

5y+28

Back to the equation:

-(5y+28)



We add all the numbers together, and all the variables

9y-(5y+28)+12=0

We get rid of parentheses

9y-5y-28+12=0

We add all the numbers together, and all the variables

4y-16=0

We move all terms containing y to the left, all other terms to the right

4y=16

y=16/4

y=4

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