(7z)/3-2=3z-9

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Solution for (7z)/3-2=3z-9 equation: 



(7z)/3-2=3z-9

We move all terms to the left:

(7z)/3-2-(3z-9)=0

We get rid of parentheses

7z/3-3z+9-2=0

We multiply all the terms by the denominator


7z-3z*3+9*3-2*3=0

We add all the numbers together, and all the variables

7z-3z*3+21=0

Wy multiply elements

7z-9z+21=0

We add all the numbers together, and all the variables

-2z+21=0

We move all terms containing z to the left, all other terms to the right

-2z=-21

z=-21/-2

z=10+1/2

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