(7z+12)=(11z-28)

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Solution for (7z+12)=(11z-28) equation: 



(7z+12)=(11z-28)

We move all terms to the left:

(7z+12)-((11z-28))=0

We get rid of parentheses

7z-((11z-28))+12=0



We calculate terms in parentheses: -((11z-28)), so:

(11z-28)

We get rid of parentheses

11z-28

Back to the equation:

-(11z-28)



We get rid of parentheses

7z-11z+28+12=0

We add all the numbers together, and all the variables

-4z+40=0

We move all terms containing z to the left, all other terms to the right

-4z=-40

z=-40/-4

z=+10

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