(7z+2)+(3z+-5)=15

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Solution for (7z+2)+(3z+-5)=15 equation: 



(7z+2)+(3z+-5)=15

We move all terms to the left:

(7z+2)+(3z+-5)-(15)=0

We add all the numbers together, and all the variables

(7z+2)+(3z-5)-15=0

We get rid of parentheses

7z+3z+2-5-15=0

We add all the numbers together, and all the variables

10z-18=0

We move all terms containing z to the left, all other terms to the right

10z=18

z=18/10

z=1+4/5

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