(7z+2)-(3x-5)=15

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Solution for (7z+2)-(3x-5)=15 equation:


Simplifying
(7z + 2) + -1(3x + -5) = 15

Reorder the terms:
(2 + 7z) + -1(3x + -5) = 15

Remove parenthesis around (2 + 7z)
2 + 7z + -1(3x + -5) = 15

Reorder the terms:
2 + 7z + -1(-5 + 3x) = 15
2 + 7z + (-5 * -1 + 3x * -1) = 15
2 + 7z + (5 + -3x) = 15

Reorder the terms:
2 + 5 + -3x + 7z = 15

Combine like terms: 2 + 5 = 7
7 + -3x + 7z = 15

Solving
7 + -3x + 7z = 15

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + -3x + -7 + 7z = 15 + -7

Reorder the terms:
7 + -7 + -3x + 7z = 15 + -7

Combine like terms: 7 + -7 = 0
0 + -3x + 7z = 15 + -7
-3x + 7z = 15 + -7

Combine like terms: 15 + -7 = 8
-3x + 7z = 8

Add '-7z' to each side of the equation.
-3x + 7z + -7z = 8 + -7z

Combine like terms: 7z + -7z = 0
-3x + 0 = 8 + -7z
-3x = 8 + -7z

Divide each side by '-3'.
x = -2.666666667 + 2.333333333z

Simplifying
x = -2.666666667 + 2.333333333z

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