(7z+2)-(3z+5)=15

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Solution for (7z+2)-(3z+5)=15 equation:


Simplifying
(7z + 2) + -1(3z + 5) = 15

Reorder the terms:
(2 + 7z) + -1(3z + 5) = 15

Remove parenthesis around (2 + 7z)
2 + 7z + -1(3z + 5) = 15

Reorder the terms:
2 + 7z + -1(5 + 3z) = 15
2 + 7z + (5 * -1 + 3z * -1) = 15
2 + 7z + (-5 + -3z) = 15

Reorder the terms:
2 + -5 + 7z + -3z = 15

Combine like terms: 2 + -5 = -3
-3 + 7z + -3z = 15

Combine like terms: 7z + -3z = 4z
-3 + 4z = 15

Solving
-3 + 4z = 15

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + 4z = 15 + 3

Combine like terms: -3 + 3 = 0
0 + 4z = 15 + 3
4z = 15 + 3

Combine like terms: 15 + 3 = 18
4z = 18

Divide each side by '4'.
z = 4.5

Simplifying
z = 4.5

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