(7z+2)-(3z-5)=15

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Solution for (7z+2)-(3z-5)=15 equation:


Simplifying
(7z + 2) + -1(3z + -5) = 15

Reorder the terms:
(2 + 7z) + -1(3z + -5) = 15

Remove parenthesis around (2 + 7z)
2 + 7z + -1(3z + -5) = 15

Reorder the terms:
2 + 7z + -1(-5 + 3z) = 15
2 + 7z + (-5 * -1 + 3z * -1) = 15
2 + 7z + (5 + -3z) = 15

Reorder the terms:
2 + 5 + 7z + -3z = 15

Combine like terms: 2 + 5 = 7
7 + 7z + -3z = 15

Combine like terms: 7z + -3z = 4z
7 + 4z = 15

Solving
7 + 4z = 15

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + -7 + 4z = 15 + -7

Combine like terms: 7 + -7 = 0
0 + 4z = 15 + -7
4z = 15 + -7

Combine like terms: 15 + -7 = 8
4z = 8

Divide each side by '4'.
z = 2

Simplifying
z = 2

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