(7z-4)=(5z+20)

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Solution for (7z-4)=(5z+20) equation: 



(7z-4)=(5z+20)

We move all terms to the left:

(7z-4)-((5z+20))=0

We get rid of parentheses

7z-((5z+20))-4=0



We calculate terms in parentheses: -((5z+20)), so:

(5z+20)

We get rid of parentheses

5z+20

Back to the equation:

-(5z+20)



We get rid of parentheses

7z-5z-20-4=0

We add all the numbers together, and all the variables

2z-24=0

We move all terms containing z to the left, all other terms to the right

2z=24

z=24/2

z=12

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