(8(2-z))/7=-z

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Solution for (8(2-z))/7=-z equation: 



(8(2-z))/7=-z

We move all terms to the left:

(8(2-z))/7-(-z)=0

We add all the numbers together, and all the variables

(8(-1z+2))/7-(-1z)=0

We get rid of parentheses

(8(-1z+2))/7+1z=0

We multiply all the terms by the denominator


(8(-1z+2))+1z*7=0



We calculate terms in parentheses: +(8(-1z+2)), so:

8(-1z+2)

We multiply parentheses

-8z+16

Back to the equation:

+(-8z+16)



Wy multiply elements

(-8z+16)+7z=0

We get rid of parentheses

-8z+7z+16=0

We add all the numbers together, and all the variables

-1z+16=0

We move all terms containing z to the left, all other terms to the right

-z=-16

z=-16/-1

z=+16

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