(8(3x+2)+2(3x+4))/(1-2x)=-28

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Solution for (8(3x+2)+2(3x+4))/(1-2x)=-28 equation: 



(8(3x+2)+2(3x+4))/(1-2x)=-28

We move all terms to the left:

(8(3x+2)+2(3x+4))/(1-2x)-(-28)=0



Domain of the equation: (1-2x)!=0

We move all terms containing x to the left, all other terms to the right

-2x!=-1

x!=-1/-2

x!=1/2

x∈R



We add all the numbers together, and all the variables

(8(3x+2)+2(3x+4))/(-2x+1)-(-28)=0

We add all the numbers together, and all the variables

(8(3x+2)+2(3x+4))/(-2x+1)+28=0

We multiply all the terms by the denominator


(8(3x+2)+2(3x+4))+28*(-2x+1)=0



We calculate terms in parentheses: +(8(3x+2)+2(3x+4)), so:

8(3x+2)+2(3x+4)

We multiply parentheses

24x+6x+16+8

We add all the numbers together, and all the variables

30x+24

Back to the equation:

+(30x+24)



We multiply parentheses

(30x+24)-56x+28=0

We get rid of parentheses

30x-56x+24+28=0

We add all the numbers together, and all the variables

-26x+52=0

We move all terms containing x to the left, all other terms to the right

-26x=-52

x=-52/-26

x=+2

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