(8)/(2x+2)=(x)/(10.5)

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Solution for (8)/(2x+2)=(x)/(10.5) equation: 



(8)/(2x+2)=(x)/(10.5)

We move all terms to the left:

(8)/(2x+2)-((x)/(10.5))=0



Domain of the equation: (2x+2)!=0

We move all terms containing x to the left, all other terms to the right

2x!=-2

x!=-2/2

x!=-1

x∈R



We calculate fractions


()/((2x+2)*(10.5)))+(-(x*(2x+2))/((2x+2)*(10.5)))=0



We calculate terms in parentheses: -(x*(2x+2))/((2x+2)*(10.5))), so:

x*(2x+2))/((2x+2)*(10.5))

We multiply all the terms by the denominator


x*(2x+2))

We multiply parentheses

2x^2+2x^2

We add all the numbers together, and all the variables

4x^2

Back to the equation:

-(4x^2)



determiningTheFunctionDomain
-4x^2+()/((2x+2)*(10.5)))+(=0

We multiply all the terms by the denominator


-4x^2*((2x+2)*(10.5)))+(+()=0

We add all the numbers together, and all the variables

-4x^2*((2x+2)*(10.5)))+(=0

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