(8+(2x-10))=3x+12

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Solution for (8+(2x-10))=3x+12 equation: 



(8+(2x-10))=3x+12

We move all terms to the left:

(8+(2x-10))-(3x+12)=0

We get rid of parentheses

(8+(2x-10))-3x-12=0



We calculate terms in parentheses: +(8+(2x-10)), so:

8+(2x-10)

determiningTheFunctionDomain
(2x-10)+8

We get rid of parentheses

2x-10+8

We add all the numbers together, and all the variables

2x-2

Back to the equation:

+(2x-2)



We add all the numbers together, and all the variables

-3x+(2x-2)-12=0

We get rid of parentheses

-3x+2x-2-12=0

We add all the numbers together, and all the variables

-1x-14=0

We move all terms containing x to the left, all other terms to the right

-x=14

x=14/-1

x=-14

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