(8+16)8=z2

Solution for (8+16)8=z2 equation:

(8+16)8=z2

We move all terms to the left:

(8+16)8-(z2)=0

We add all the numbers together, and all the variables

-z2+248=0

We add all the numbers together, and all the variables

-1z^2+248=0

a = -1; b = 0; c = +248;
Δ = b2-4ac
Δ = 02-4·(-1)·248
Δ = 992
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{992}=\sqrt{16*62}=\sqrt{16}*\sqrt{62}=4\sqrt{62}$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{62}}{2*-1}=\frac{0-4\sqrt{62}}{-2}
=-\frac{4\sqrt{62}}{-2}
=-\frac{2\sqrt{62}}{-1}
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{62}}{2*-1}=\frac{0+4\sqrt{62}}{-2}
=\frac{4\sqrt{62}}{-2}
=\frac{2\sqrt{62}}{-1}
$