(8+2i)(8-2i)=

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Solution for (8+2i)(8-2i)= equation:


Simplifying
(8 + 2i)(8 + -2i) = 0

Multiply (8 + 2i) * (8 + -2i)
(8(8 + -2i) + 2i * (8 + -2i)) = 0
((8 * 8 + -2i * 8) + 2i * (8 + -2i)) = 0
((64 + -16i) + 2i * (8 + -2i)) = 0
(64 + -16i + (8 * 2i + -2i * 2i)) = 0
(64 + -16i + (16i + -4i2)) = 0

Combine like terms: -16i + 16i = 0
(64 + 0 + -4i2) = 0
(64 + -4i2) = 0

Solving
64 + -4i2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-64' to each side of the equation.
64 + -64 + -4i2 = 0 + -64

Combine like terms: 64 + -64 = 0
0 + -4i2 = 0 + -64
-4i2 = 0 + -64

Combine like terms: 0 + -64 = -64
-4i2 = -64

Divide each side by '-4'.
i2 = 16

Simplifying
i2 = 16

Take the square root of each side:
i = {-4, 4}

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