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(8+2x)(12+2x)=0
We add all the numbers together, and all the variables
(2x+8)(2x+12)=0
We multiply parentheses ..
(+4x^2+24x+16x+96)=0
We get rid of parentheses
4x^2+24x+16x+96=0
We add all the numbers together, and all the variables
4x^2+40x+96=0
a = 4; b = 40; c = +96;
Δ = b2-4ac
Δ = 402-4·4·96
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-8}{2*4}=\frac{-48}{8} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+8}{2*4}=\frac{-32}{8} =-4 $
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