(8+3x)=(7-3x)+1

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Solution for (8+3x)=(7-3x)+1 equation: 



(8+3x)=(7-3x)+1

We move all terms to the left:

(8+3x)-((7-3x)+1)=0

We add all the numbers together, and all the variables

(3x+8)-((-3x+7)+1)=0

We get rid of parentheses

3x-((-3x+7)+1)+8=0



We calculate terms in parentheses: -((-3x+7)+1), so:

(-3x+7)+1

We get rid of parentheses

-3x+7+1

We add all the numbers together, and all the variables

-3x+8

Back to the equation:

-(-3x+8)



We get rid of parentheses

3x+3x-8+8=0

We add all the numbers together, and all the variables

6x=0

x=0/6

x=0

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