(8+3y)=38-3(10+y)

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Solution for (8+3y)=38-3(10+y) equation: 



(8+3y)=38-3(10+y)

We move all terms to the left:

(8+3y)-(38-3(10+y))=0

We add all the numbers together, and all the variables

(3y+8)-(38-3(y+10))=0

We get rid of parentheses

3y-(38-3(y+10))+8=0



We calculate terms in parentheses: -(38-3(y+10)), so:

38-3(y+10)

determiningTheFunctionDomain
-3(y+10)+38

We multiply parentheses

-3y-30+38

We add all the numbers together, and all the variables

-3y+8

Back to the equation:

-(-3y+8)



We get rid of parentheses

3y+3y-8+8=0

We add all the numbers together, and all the variables

6y=0

y=0/6

y=0

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