(8+4x)(8+4x)=0

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Solution for (8+4x)(8+4x)=0 equation: 



(8+4x)(8+4x)=0

We add all the numbers together, and all the variables

(4x+8)(4x+8)=0

We multiply parentheses ..

(+16x^2+32x+32x+64)=0

We get rid of parentheses

16x^2+32x+32x+64=0

We add all the numbers together, and all the variables

16x^2+64x+64=0

a = 16; b = 64; c = +64;
Δ = b2-4ac
Δ = 642-4·16·64
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-64}{32}=-2$

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