(8+6i)(4+2i)=(4+2i)(8+6i)

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Solution for (8+6i)(4+2i)=(4+2i)(8+6i) equation: 



(8+6i)(4+2i)=(4+2i)(8+6i)

We move all terms to the left:

(8+6i)(4+2i)-((4+2i)(8+6i))=0

We add all the numbers together, and all the variables

(6i+8)(2i+4)-((2i+4)(6i+8))=0

We multiply parentheses ..

(+12i^2+24i+16i+32)-((2i+4)(6i+8))=0



We calculate terms in parentheses: -((2i+4)(6i+8)), so:

(2i+4)(6i+8)

We multiply parentheses ..

(+12i^2+16i+24i+32)

We get rid of parentheses

12i^2+16i+24i+32

We add all the numbers together, and all the variables

12i^2+40i+32

Back to the equation:

-(12i^2+40i+32)



We get rid of parentheses

12i^2-12i^2+24i+16i-40i+32-32=0

We add all the numbers together, and all the variables

=0

i=0/1

i=0

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