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(8+6x)(4x+2)=30
We move all terms to the left:
(8+6x)(4x+2)-(30)=0
We add all the numbers together, and all the variables
(6x+8)(4x+2)-30=0
We multiply parentheses ..
(+24x^2+12x+32x+16)-30=0
We get rid of parentheses
24x^2+12x+32x+16-30=0
We add all the numbers together, and all the variables
24x^2+44x-14=0
a = 24; b = 44; c = -14;
Δ = b2-4ac
Δ = 442-4·24·(-14)
Δ = 3280
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3280}=\sqrt{16*205}=\sqrt{16}*\sqrt{205}=4\sqrt{205}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-4\sqrt{205}}{2*24}=\frac{-44-4\sqrt{205}}{48} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+4\sqrt{205}}{2*24}=\frac{-44+4\sqrt{205}}{48} $
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