(8+i)(3-4i)=

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Solution for (8+i)(3-4i)= equation:


Simplifying
(8 + i)(3 + -4i) = 0

Multiply (8 + i) * (3 + -4i)
(8(3 + -4i) + i(3 + -4i)) = 0
((3 * 8 + -4i * 8) + i(3 + -4i)) = 0
((24 + -32i) + i(3 + -4i)) = 0
(24 + -32i + (3 * i + -4i * i)) = 0
(24 + -32i + (3i + -4i2)) = 0

Combine like terms: -32i + 3i = -29i
(24 + -29i + -4i2) = 0

Solving
24 + -29i + -4i2 = 0

Solving for variable 'i'.

Factor a trinomial.
(3 + -4i)(8 + i) = 0

Subproblem 1

Set the factor '(3 + -4i)' equal to zero and attempt to solve: Simplifying 3 + -4i = 0 Solving 3 + -4i = 0 Move all terms containing i to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -4i = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -4i = 0 + -3 -4i = 0 + -3 Combine like terms: 0 + -3 = -3 -4i = -3 Divide each side by '-4'. i = 0.75 Simplifying i = 0.75

Subproblem 2

Set the factor '(8 + i)' equal to zero and attempt to solve: Simplifying 8 + i = 0 Solving 8 + i = 0 Move all terms containing i to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + i = 0 + -8 Combine like terms: 8 + -8 = 0 0 + i = 0 + -8 i = 0 + -8 Combine like terms: 0 + -8 = -8 i = -8 Simplifying i = -8

Solution

i = {0.75, -8}

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