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(8+u)(5u+4)=0
We add all the numbers together, and all the variables
(u+8)(5u+4)=0
We multiply parentheses ..
(+5u^2+4u+40u+32)=0
We get rid of parentheses
5u^2+4u+40u+32=0
We add all the numbers together, and all the variables
5u^2+44u+32=0
a = 5; b = 44; c = +32;
Δ = b2-4ac
Δ = 442-4·5·32
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-36}{2*5}=\frac{-80}{10} =-8 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+36}{2*5}=\frac{-8}{10} =-4/5 $
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