(8+v)(3v-4)=0

Solution for (8+v)(3v-4)=0 equation:

(8+v)(3v-4)=0

We add all the numbers together, and all the variables

(v+8)(3v-4)=0

We multiply parentheses ..

(+3v^2-4v+24v-32)=0

We get rid of parentheses

3v^2-4v+24v-32=0

We add all the numbers together, and all the variables

3v^2+20v-32=0

a = 3; b = 20; c = -32;
Δ = b2-4ac
Δ = 202-4·3·(-32)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-28}{2*3}=\frac{-48}{6}
=-8
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+28}{2*3}=\frac{8}{6}
=1+1/3
$