(8+v)(4v-2)=0

Solution for (8+v)(4v-2)=0 equation:

(8+v)(4v-2)=0

We add all the numbers together, and all the variables

(v+8)(4v-2)=0

We multiply parentheses ..

(+4v^2-2v+32v-16)=0

We get rid of parentheses

4v^2-2v+32v-16=0

We add all the numbers together, and all the variables

4v^2+30v-16=0

a = 4; b = 30; c = -16;
Δ = b2-4ac
Δ = 302-4·4·(-16)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-34}{2*4}=\frac{-64}{8}
=-8
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+34}{2*4}=\frac{4}{8}
=1/2
$