(8+w)(4w+3)=0

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Solution for (8+w)(4w+3)=0 equation:



(8+w)(4w+3)=0
We add all the numbers together, and all the variables
(w+8)(4w+3)=0
We multiply parentheses ..
(+4w^2+3w+32w+24)=0
We get rid of parentheses
4w^2+3w+32w+24=0
We add all the numbers together, and all the variables
4w^2+35w+24=0
a = 4; b = 35; c = +24;
Δ = b2-4ac
Δ = 352-4·4·24
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-29}{2*4}=\frac{-64}{8} =-8 $
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+29}{2*4}=\frac{-6}{8} =-3/4 $

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