(8+x)(28+x)=(13+x)(18+x)

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Solution for (8+x)(28+x)=(13+x)(18+x) equation:



(8+x)(28+x)=(13+x)(18+x)
We move all terms to the left:
(8+x)(28+x)-((13+x)(18+x))=0
We add all the numbers together, and all the variables
(x+8)(x+28)-((x+13)(x+18))=0
We multiply parentheses ..
(+x^2+28x+8x+224)-((x+13)(x+18))=0
We calculate terms in parentheses: -((x+13)(x+18)), so:
(x+13)(x+18)
We multiply parentheses ..
(+x^2+18x+13x+234)
We get rid of parentheses
x^2+18x+13x+234
We add all the numbers together, and all the variables
x^2+31x+234
Back to the equation:
-(x^2+31x+234)
We get rid of parentheses
x^2-x^2+28x+8x-31x+224-234=0
We add all the numbers together, and all the variables
5x-10=0
We move all terms containing x to the left, all other terms to the right
5x=10
x=10/5
x=2

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