(8+x)(x-1)=(x+1)(x-2)+2

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Solution for (8+x)(x-1)=(x+1)(x-2)+2 equation: 



(8+x)(x-1)=(x+1)(x-2)+2

We move all terms to the left:

(8+x)(x-1)-((x+1)(x-2)+2)=0

We add all the numbers together, and all the variables

(x+8)(x-1)-((x+1)(x-2)+2)=0

We multiply parentheses ..

(+x^2-1x+8x-8)-((x+1)(x-2)+2)=0



We calculate terms in parentheses: -((x+1)(x-2)+2), so:

(x+1)(x-2)+2

We multiply parentheses ..

(+x^2-2x+x-2)+2

We get rid of parentheses

x^2-2x+x-2+2

We add all the numbers together, and all the variables

x^2-1x

Back to the equation:

-(x^2-1x)



We get rid of parentheses

x^2-x^2-1x+8x+1x-8=0

We add all the numbers together, and all the variables

8x-8=0

We move all terms containing x to the left, all other terms to the right

8x=8

x=8/8

x=1

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