(8+x-2)(x-2)=(8+x)(x)+68

Solution for (8+x-2)(x-2)=(8+x)(x)+68 equation:

(8+x-2)(x-2)=(8+x)(x)+68

We move all terms to the left:

(8+x-2)(x-2)-((8+x)(x)+68)=0

We add all the numbers together, and all the variables

(x+6)(x-2)-((x+8)x+68)=0

We multiply parentheses ..

(+x^2-2x+6x-12)-((x+8)x+68)=0


We calculate terms in parentheses: -((x+8)x+68), so:

(x+8)x+68

We multiply parentheses

x^2+8x+68

Back to the equation:

-(x^2+8x+68)


We get rid of parentheses

x^2-x^2-2x+6x-8x-12-68=0

We add all the numbers together, and all the variables

-4x-80=0

We move all terms containing x to the left, all other terms to the right

-4x=80

x=80/-4

x=-20