(8-3i)(-7-6i)=0

Solution for (8-3i)(-7-6i)=0 equation:

(8-3i)(-7-6i)=0

We add all the numbers together, and all the variables

(-3i+8)(-6i-7)=0

We multiply parentheses ..

(+18i^2+21i-48i-56)=0

We get rid of parentheses

18i^2+21i-48i-56=0

We add all the numbers together, and all the variables

18i^2-27i-56=0

a = 18; b = -27; c = -56;
Δ = b2-4ac
Δ = -272-4·18·(-56)
Δ = 4761
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4761}=69$
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-69}{2*18}=\frac{-42}{36}
=-1+1/6
$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+69}{2*18}=\frac{96}{36}
=2+2/3
$