(8-3x)2+(5-4x)2-6=(9-5x)2+20x-4

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Solution for (8-3x)2+(5-4x)2-6=(9-5x)2+20x-4 equation: 



(8-3x)2+(5-4x)2-6=(9-5x)2+20x-4

We move all terms to the left:

(8-3x)2+(5-4x)2-6-((9-5x)2+20x-4)=0

We add all the numbers together, and all the variables

(-3x+8)2+(-4x+5)2-((-5x+9)2+20x-4)-6=0

We multiply parentheses

-6x-8x-((-5x+9)2+20x-4)+16+10-6=0



We calculate terms in parentheses: -((-5x+9)2+20x-4), so:

(-5x+9)2+20x-4

We add all the numbers together, and all the variables

20x+(-5x+9)2-4

We multiply parentheses

20x-10x+18-4

We add all the numbers together, and all the variables

10x+14

Back to the equation:

-(10x+14)



We add all the numbers together, and all the variables

-14x-(10x+14)+20=0

We get rid of parentheses

-14x-10x-14+20=0

We add all the numbers together, and all the variables

-24x+6=0

We move all terms containing x to the left, all other terms to the right

-24x=-6

x=-6/-24

x=1/4

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