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(8-5x)(2x+7)=0
We add all the numbers together, and all the variables
(-5x+8)(2x+7)=0
We multiply parentheses ..
(-10x^2-35x+16x+56)=0
We get rid of parentheses
-10x^2-35x+16x+56=0
We add all the numbers together, and all the variables
-10x^2-19x+56=0
a = -10; b = -19; c = +56;
Δ = b2-4ac
Δ = -192-4·(-10)·56
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2601}=51$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-51}{2*-10}=\frac{-32}{-20} =1+3/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+51}{2*-10}=\frac{70}{-20} =-3+1/2 $
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