(8-5y)-(4+3y)=-8y+4

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Solution for (8-5y)-(4+3y)=-8y+4 equation: 


Simplifying
(8 + -5y) + -1(4 + 3y) = -8y + 4

Remove parenthesis around (8 + -5y)
8 + -5y + -1(4 + 3y) = -8y + 4
8 + -5y + (4 * -1 + 3y * -1) = -8y + 4
8 + -5y + (-4 + -3y) = -8y + 4

Reorder the terms:
8 + -4 + -5y + -3y = -8y + 4

Combine like terms: 8 + -4 = 4
4 + -5y + -3y = -8y + 4

Combine like terms: -5y + -3y = -8y
4 + -8y = -8y + 4

Reorder the terms:
4 + -8y = 4 + -8y

Add '-4' to each side of the equation.
4 + -4 + -8y = 4 + -4 + -8y

Combine like terms: 4 + -4 = 0
0 + -8y = 4 + -4 + -8y
-8y = 4 + -4 + -8y

Combine like terms: 4 + -4 = 0
-8y = 0 + -8y
-8y = -8y

Add '8y' to each side of the equation.
-8y + 8y = -8y + 8y

Combine like terms: -8y + 8y = 0
0 = -8y + 8y

Combine like terms: -8y + 8y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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