(8-u)(2u+3)=0

Solution for (8-u)(2u+3)=0 equation:

(8-u)(2u+3)=0

We add all the numbers together, and all the variables

(-1u+8)(2u+3)=0

We multiply parentheses ..

(-2u^2-3u+16u+24)=0

We get rid of parentheses

-2u^2-3u+16u+24=0

We add all the numbers together, and all the variables

-2u^2+13u+24=0

a = -2; b = 13; c = +24;
Δ = b2-4ac
Δ = 132-4·(-2)·24
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-19}{2*-2}=\frac{-32}{-4}
=+8
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+19}{2*-2}=\frac{6}{-4}
=-1+1/2
$