(8-v)(3v+7)=0

Solution for (8-v)(3v+7)=0 equation:

(8-v)(3v+7)=0

We add all the numbers together, and all the variables

(-1v+8)(3v+7)=0

We multiply parentheses ..

(-3v^2-7v+24v+56)=0

We get rid of parentheses

-3v^2-7v+24v+56=0

We add all the numbers together, and all the variables

-3v^2+17v+56=0

a = -3; b = 17; c = +56;
Δ = b2-4ac
Δ = 172-4·(-3)·56
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-31}{2*-3}=\frac{-48}{-6}
=+8
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+31}{2*-3}=\frac{14}{-6}
=-2+1/3
$