(8-v)(8+v)=0

Solution for (8-v)(8+v)=0 equation:

(8-v)(8+v)=0

We add all the numbers together, and all the variables

(-1v+8)(v+8)=0

We multiply parentheses ..

(-1v^2-8v+8v+64)=0

We get rid of parentheses

-1v^2-8v+8v+64=0

We add all the numbers together, and all the variables

-1v^2+64=0

a = -1; b = 0; c = +64;
Δ = b2-4ac
Δ = 02-4·(-1)·64
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16}{2*-1}=\frac{-16}{-2}
=+8
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16}{2*-1}=\frac{16}{-2}
=-8
$