(8-x)(12-x)=1/3(96)

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Solution for (8-x)(12-x)=1/3(96) equation: 



(8-x)(12-x)=1/3(96)

We move all terms to the left:

(8-x)(12-x)-(1/3(96))=0

We add all the numbers together, and all the variables

(-1x+8)(-1x+12)-(+1/396)=0

We get rid of parentheses

(-1x+8)(-1x+12)-1/396=0

We multiply parentheses ..

(+x^2-12x-8x+96)-1/396=0

We multiply all the terms by the denominator


((+x^2-12x-8x+96))*396-1=0

We move all terms containing x to the left, all other terms to the right

((+x^2-12x-8x+96))*396=1

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