(8-x)*((7-x)(6-x)-3)-(6-2x)-(6-x)=0

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Solution for (8-x)*((7-x)(6-x)-3)-(6-2x)-(6-x)=0 equation: 



(8-x)((7-x)(6-x)-3)-(6-2x)-(6-x)=0

We add all the numbers together, and all the variables

(-1x+8)((-1x+7)(-1x+6)-3)-(-2x+6)-(-1x+6)=0

We get rid of parentheses

(-1x+8)((-1x+7)(-1x+6)-3)+2x+1x-6-6=0

We multiply parentheses ..

(-1x+8)((+x^2-6x-7x+42)-3)+2x+1x-6-6=0



We calculate terms in parentheses: +(-1x+8)((+x^2-6x-7x+42)-3), so:

-1x+8)((+x^2-6x-7x+42)-3

determiningTheFunctionDomain
8)((+x^2-6x-7x+42)-1x-3

Back to the equation:

+(8)((+x^2-6x-7x+42)-1x-3)



We add all the numbers together, and all the variables

8((+x^2-6x-7x+42)-1x-3)+3x-12=0

We move all terms containing x to the left, all other terms to the right

8((+x^2-6x-7x+42)-1x-3)+3x=12

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