(8-x)/(x+5)+(x+3)/x=0

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Solution for (8-x)/(x+5)+(x+3)/x=0 equation: 



(8-x)/(x+5)+(x+3)/x=0



Domain of the equation: (x+5)!=0

We move all terms containing x to the left, all other terms to the right

x!=-5

x∈R





Domain of the equation: x!=0

x∈R



We add all the numbers together, and all the variables

(-1x+8)/(x+5)+(x+3)/x=0

We calculate fractions


(-1x^2+8x)/(x^2+5x)+((x+3)*(x+5))/(x^2+5x)=0



We calculate terms in parentheses: +((x+3)*(x+5))/(x^2+5x), so:

(x+3)*(x+5))/(x^2+5x

We add all the numbers together, and all the variables

5x+(x+3)*(x+5))/(x^2

We multiply all the terms by the denominator


5x*(x^2+(x+3)*(x+5))

Back to the equation:

+(5x*(x^2+(x+3)*(x+5)))



We multiply all the terms by the denominator


(-1x^2+8x)+((5x*(x^2+(x+3)*(x+5))))*(x^2+5x)=0



We calculate terms in parentheses: +((5x*(x^2+(x+3)*(x+5))))*(x^2+5x), so:

(5x*(x^2+(x+3)*(x+5))))*(x^2+5x

We add all the numbers together, and all the variables

5x+(5x*(x^2+(x+3)*(x+5))))*(x^2

Back to the equation:

+(5x+(5x*(x^2+(x+3)*(x+5))))*(x^2)



We get rid of parentheses

-1x^2+8x+(5x+(5x*(x^2+(x+3)*(x+5))))*x^2=0

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