(8-x)/3=(x+5)/10

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Solution for (8-x)/3=(x+5)/10 equation: 



(8-x)/3=(x+5)/10

We move all terms to the left:

(8-x)/3-((x+5)/10)=0

We add all the numbers together, and all the variables

(-1x+8)/3-((x+5)/10)=0

We calculate fractions


(-x)/()+(-((x+5)*3)/()=0



We calculate terms in parentheses: +(-((x+5)*3)/(), so:

-((x+5)*3)/(

We multiply all the terms by the denominator


-((x+5)*3)



We calculate terms in parentheses: -((x+5)*3), so:

(x+5)*3

We multiply parentheses

3x+15

Back to the equation:

-(3x+15)



We get rid of parentheses

-3x-15

Back to the equation:

+(-3x-15)



We add all the numbers together, and all the variables

(-1x)/()+(-3x-15)=0

We get rid of parentheses

(-1x)/()-3x-15=0

We multiply all the terms by the denominator


(-1x)-3x*()-15*()=0

We add all the numbers together, and all the variables

(-1x)-3x*()=0

We get rid of parentheses

-1x-3x*()=0

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