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(8-y)(8=y)
We move all terms to the left:
(8-y)(8-(y))=0
We add all the numbers together, and all the variables
(-1y+8)(-1y+8)=0
We multiply parentheses ..
(+y^2-8y-8y+64)=0
We get rid of parentheses
y^2-8y-8y+64=0
We add all the numbers together, and all the variables
y^2-16y+64=0
a = 1; b = -16; c = +64;
Δ = b2-4ac
Δ = -162-4·1·64
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$y=\frac{-b}{2a}=\frac{16}{2}=8$
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