(8/11)(x-10)=64

Solution for (8/11)(x-10)=64 equation:

(8/11)(x-10)=64

We move all terms to the left:

(8/11)(x-10)-(64)=0


Domain of the equation: 11)(x-10)!=0

x∈R


We add all the numbers together, and all the variables

(+8/11)(x-10)-64=0

We multiply parentheses ..

(+8x^2+8/11*-10)-64=0

We multiply all the terms by the denominator


(+8x^2+8-64*11*-10)=0

We get rid of parentheses

8x^2+8-10-64*11*=0

We add all the numbers together, and all the variables

8x^2=0

a = 8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·8·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{16}=0$