(8/3)y=48

Solution for (8/3)y=48 equation:

(8/3)y=48

We move all terms to the left:

(8/3)y-(48)=0


Domain of the equation: 3)y!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

(+8/3)y-48=0

We multiply parentheses

8y^2-48=0

a = 8; b = 0; c = -48;
Δ = b2-4ac
Δ = 02-4·8·(-48)
Δ = 1536
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1536}=\sqrt{256*6}=\sqrt{256}*\sqrt{6}=16\sqrt{6}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{6}}{2*8}=\frac{0-16\sqrt{6}}{16}
=-\frac{16\sqrt{6}}{16}
=-\sqrt{6}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{6}}{2*8}=\frac{0+16\sqrt{6}}{16}
=\frac{16\sqrt{6}}{16}
=\sqrt{6}
$