(8/9)k+(8/9)=8-(3/2)k

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Solution for (8/9)k+(8/9)=8-(3/2)k equation: 



(8/9)k+(8/9)=8-(3/2)k

We move all terms to the left:

(8/9)k+(8/9)-(8-(3/2)k)=0



Domain of the equation: 9)k!=0

k!=0/1

k!=0

k∈R





Domain of the equation: 2)k)!=0

k!=0/1

k!=0

k∈R



We add all the numbers together, and all the variables

(+8/9)k-(8-(+3/2)k)+(+8/9)=0

We multiply parentheses

8k^2-(8-(+3/2)k)+(+8/9)=0

We get rid of parentheses

8k^2-(8-(+3/2)k)+8/9=0

We calculate fractions


8k^2+()/2k)*9)+16k/2k)*9)=0

We can not solve this equation

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