(8/9)z=24

Solution for (8/9)z=24 equation:

(8/9)z=24

We move all terms to the left:

(8/9)z-(24)=0


Domain of the equation: 9)z!=0

z!=0/1

z!=0

z∈R


We add all the numbers together, and all the variables

(+8/9)z-24=0

We multiply parentheses

8z^2-24=0

a = 8; b = 0; c = -24;
Δ = b2-4ac
Δ = 02-4·8·(-24)
Δ = 768
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{768}=\sqrt{256*3}=\sqrt{256}*\sqrt{3}=16\sqrt{3}$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{3}}{2*8}=\frac{0-16\sqrt{3}}{16}
=-\frac{16\sqrt{3}}{16}
=-\sqrt{3}
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{3}}{2*8}=\frac{0+16\sqrt{3}}{16}
=\frac{16\sqrt{3}}{16}
=\sqrt{3}
$