(8/x)+(3/(x+9))=2

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Solution for (8/x)+(3/(x+9))=2 equation:


D( x )

x = 0

x+9 = 0

x = 0

x = 0

x+9 = 0

x+9 = 0

x+9 = 0 // - 9

x = -9

x in (-oo:-9) U (-9:0) U (0:+oo)

3/(x+9)+8/x = 2 // - 2

3/(x+9)+8/x-2 = 0

(3*x)/(x*(x+9))+(8*(x+9))/(x*(x+9))+(-2*x*(x+9))/(x*(x+9)) = 0

8*(x+9)-2*x*(x+9)+3*x = 0

11*x-2*x^2-18*x+72 = 0

72-2*x^2-7*x = 0

72-2*x^2-7*x = 0

72-2*x^2-7*x = 0

DELTA = (-7)^2-(-2*4*72)

DELTA = 625

DELTA > 0

x = (625^(1/2)+7)/(-2*2) or x = (7-625^(1/2))/(-2*2)

x = -8 or x = 9/2

(x+8)*(x-9/2) = 0

((x+8)*(x-9/2))/(x*(x+9)) = 0

((x+8)*(x-9/2))/(x*(x+9)) = 0 // * x*(x+9)

(x+8)*(x-9/2) = 0

( x+8 )

x+8 = 0 // - 8

x = -8

( x-9/2 )

x-9/2 = 0 // + 9/2

x = 9/2

x in { -8, 9/2 }

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